The rate constant for the first order decomposition of a certain reaction is described by the equation $\ln k (s^{-1}) = 14.34 - \frac{1.25 \times 10^{4} \ K}{T}$. The energy of activation for this reaction is

  • A
    $1.26 \times 10^{4} \ cal \ mol^{-1}$
  • B
    $4.29 \times 10^{4} \ cal \ mol^{-1}$
  • C
    $3.12 \times 10^{4} \ cal \ mol^{-1}$
  • D
    $2.50 \times 10^{4} \ cal \ mol^{-1}$

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Activation energy of a reaction is

On introducing a catalyst at $500 \, K,$ the rate constant of a first order reaction increases $2.718$ times. If the activation energy in the presence of a catalyst is $4.15 \, kJ \, mol^{-1},$ then what will be $E_a$ in the absence of a catalyst? (Value of $e = 2.718$ and $R = 8.314 \times 10^{-3} \, kJ \, K^{-1} \, mol^{-1}$)

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Activation energy is defined as:

The specific rate constant of a first-order reaction depends on .......

For an exothermic reaction $X \rightarrow Y$,the activation energy is $30 \ kJ \ mol^{-1}$. If the enthalpy change $(\Delta H)$ for the reaction is $-20 \ kJ \ mol^{-1}$,then the activation energy for the reverse reaction is . . . . . . $kJ \ mol^{-1}$.

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